A) \[n=4,l=3,m=+4,s=+1/2\]
B) \[n=4,l=4,m=-4,s=-1/2\]
C) \[n=4,l=3,m=+1,s=+1/2\]
D) \[n=3,l=2,m=-2,s=+1/2\]
Correct Answer: C
Solution :
Any sub-orbit is represented as nl such that n is the principal quantum number (in the form of values) and / is the azimuthal quantum number (its name). Value of \[l<n,\text{ }l\text{ }0\text{ }1\text{ }2\,\,3\,\,4\] \[s\,\text{ }p\,\text{ }d\,\text{ }f\,\text{ }g\] Value of m: \[-l,-l+1.......0,.......+l\] Value of s: \[+\frac{1}{2}\]or \[-\frac{1}{2}\] Thus, for\[4f:n=4,\text{ }l=3,m=\]any value between ? 3 to +3. Therefore, the correct sets of quantum number for an electron in\[4f\]orbital is \[n=4,l=3,\text{ }m=+1,\text{ }s=+\frac{1}{2}\]
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