A) \[{{[Co{{(CN)}_{6}}]}^{3-}}\]
B) \[{{[Fe{{(CN)}_{6}}]}^{3-}}\]
C) \[{{[Mn{{(CN)}_{6}}]}^{3-}}\]
D) \[{{[Cr{{(CN)}_{6}}]}^{3-}}\]
Correct Answer: A
Solution :
Hybridisation | Unpaired elctrons | Magnetic moment | ||
\[{{[Co{{(CN)}_{6}}]}^{3-}}\] | \[{{d}^{2}}s{{p}^{3}}\] | 0 | 0 | |
\[{{[Fe{{(CN)}_{6}}]}^{3-}}\] | \[{{d}^{2}}s{{p}^{3}}\] | 1 | \[\sqrt{3}\,BM\] | |
\[{{[Mn{{(CN)}_{6}}]}^{3-}}\] | \[{{d}^{2}}s{{p}^{3}}\] | 2 | \[\sqrt{8}\,BM\] | |
\[{{[Cr{{(CN)}_{6}}]}^{3-}}\] | \[{{d}^{2}}s{{p}^{3}}\] | 3 | \[\sqrt{15}\,BM\] |
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