question_answer

The current I drawn from the 5 V source will be   AIEEE  Solved  Paper-2006

A) 0.33 A  

B)                        0.5 A     

C)        0.67 A                   

D) 0.17 A

Correct Answer: B

Solution :

The given circuit can be redrawn as Which is a balanced condition of Wheatstone's bridge and hence no current flows in the centre resistor, so equivalent circuit would be as shown below. \[30\,\Omega ||15\,\Omega =10\,\Omega \]    \[\left[ \because R=\frac{30\times 15}{30+15} \right]\] So, current through the circuit, \[I=\frac{V}{R}=\frac{5}{10}=0.5\,A\]