2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2006

  • question_answer
    In an AC generator, a coil with N turns, all of the same area A and total resistance R, rotates with frequency \[\omega \] in a magnetic field B. The maximum value of emf generated in the coil is     AIEEE  Solved  Paper-2006

    A) \[NABR\,\omega \]        

    B)        \[NAB\]               

    C)         \[NABR\]           

    D)        \[NAB\,\omega \]

    Correct Answer: D

    Solution :

    The emf generated would be maximum when flux (cutting) would be maximum i.e., angle between area vector of coil and magnetic field is\[0{}^\circ \]. The emf generated is given by (as a function of time) \[e=NBA\omega \cos \omega t=NBA\omega \,\cos \theta \] \[\Rightarrow \] \[{{e}_{\max }}=NAB\omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner