JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilibrium to the end is       AIEEE  Solved  Paper-2007

    A)  \[p=\frac{{{E}_{0}}{{I}_{0}}}{2}\] 

    B)                         \[P=\sqrt{2}{{E}_{0}}{{I}_{0}}\]                

    C)         \[{{10}^{-3}}\mu C\]                     

    D)         \[(\sqrt{2},\sqrt{2})\]

    Correct Answer: A

    Solution :

    The average kinetic energy of particle \[A={{x}_{0}}{{\omega }^{2}},\text{ }\delta =\pi /4\] \[A={{x}_{0}}{{\omega }^{2}},\text{ }\delta =-\pi /4\]                     \[A={{x}_{0}}{{\omega }^{2}},\text{ }\delta =3\pi /4\] \[\eta =\]


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