JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    Equal masses of methane and oxygen are mixed in an empty container at\[\frac{5}{3}V/\mu m\]. The fraction of the total pressure exerted by oxygen is       AIEEE  Solved  Paper-2007

    A)  \[x\]                    

    B)         \[\frac{5}{3}V/\mu m\]               

    C)         \[x\]                   

    D)         \[\frac{10}{9}V/\mu m\]

    Correct Answer: C

    Solution :

    Partial pressure depends on the mole fraction. So, find the mole fraction, then calculate partial pressure. Suppose the equal mass of methane and oxygen                                 \[1\,\Omega \] Mole fraction of oxygen\[4\,\Omega \]                                                 \[3\,\Omega \] Let the total pressure = p Pressure exerted by oxygen (partial pressure) \[\frac{1}{2}(K-1)C{{V}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner