JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    In a geometric progression consisting of positive terms, each term equals the sum of the next two terms. Then, the common ratio of this progression equals       AIEEE  Solved  Paper-2007

    A)  \[{{[NiC{{l}_{4}}]}^{2-}}\]      

    B)         \[{{[PtC{{l}_{4}}]}^{2-}}\]            

    C)         \[\alpha -\]                       

    D)         \[C{{H}_{3}}-C\equiv CH+2HBr\xrightarrow[{}]{{}}\]

    Correct Answer: D

    Solution :

    Since, each term is equal to the sum of next two terms. \[\therefore \]  \[a{{r}^{n-1}}=a{{r}^{n}}+a{{r}^{n+1}}\] \[\Rightarrow \]\[1=r+{{r}^{2}}\Rightarrow {{r}^{2}}+r-1=0\] \[\Rightarrow \]\[r=\frac{\sqrt{5}-1}{2}\]                                    \[\left( \because r\ne \frac{-\sqrt{5}-1}{2} \right)\]


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