JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
    Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below:
     \[\frac{1}{2}C{{l}_{2}}(g)\xrightarrow{\frac{1}{2}{{\Delta }_{diss}}{{H}^{\Theta }}}Cl(g)\xrightarrow{{{\Delta }_{eg}}{{H}^{\Theta }}}C{{l}^{-}}\]\[(g)\xrightarrow{\frac{1}{2}{{\Delta }_{hyd}}{{H}^{\Theta }}}C{{l}^{-}}(aq)\] 
     The energy involved in the conversion of 
     \[\frac{1}{2}C{{l}_{2}}(g)\] to \[C{{l}^{-}}(aq)\] 
    (using the data, \[{{\Delta }_{diss}}H_{C{{l}_{2}}}^{\Theta }=240\,kJ\,mo{{l}^{-1}},\,{{\Delta }_{eg}}H_{Cl}^{\Theta }=-349\]\[kJ\,mo{{l}^{-1}},{{\Delta }_{hyd}}{{H}_{C{{l}^{-}}}}=-381\,kJ\,mo{{l}^{-1}})\] will be
        AIEEE  Solved  Paper-2007

    A) - 850 kJ \[mo{{l}^{-1}}\]

    B) +120 kJ \[mo{{l}^{-1}}\]                

    C) +152 kJ \[mo{{l}^{-1}}\]

    D) - 610 kJ \[mo{{l}^{-1}}\]

    Correct Answer: D

    Solution :

    \[\Delta H=\left( \frac{1}{2}\times 240 \right)+(-349)+(-381)\]    \[=-610\,kJ\,mo{{l}^{-1}}\].


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