A) 1 : 3
B) 1 : 9
C) 1 : 36
D) 1 : 1
Correct Answer: C
Solution :
Let initial moles of X and Z taken are ?a? and ?b? respectively. \[X\,\,\,\,\,2Y\] \[ZP+Q\] Moles at equilibrium \[a(1-\alpha )\] \[2a\,\alpha \] Moles at equilibrium \[b(1-\alpha )\,\,b\,\alpha \] \[b\,\alpha \] \[{{K}_{{{p}_{1}}}}=\frac{{{(2a\alpha )}^{2}}{{P}_{{{T}_{1}}}}}{a(1-\alpha )\,\,a(1+\alpha )}\] \[{{K}_{{{p}_{2}}}}=\frac{{{(b\alpha )}^{2}}{{P}_{{{T}_{2}}}}}{b(1-\alpha )\,\,b(1+\alpha )}\] \[\frac{{{K}_{{{p}_{1}}}}}{{{K}_{{{p}_{2}}}}}=\frac{4{{P}_{{{T}_{1}}}}}{{{P}_{{{T}_{2}}}}}=\frac{1}{9}\,\,\,;\,\,\,\frac{{{P}_{{{T}_{1}}}}}{{{P}_{{{T}_{2}}}}}=\frac{1}{36}\].You need to login to perform this action.
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