AIEEE Solved Paper-2007
A) 0.03 A \[{{P}_{2}}\] to \[{{P}_{1}}\]
B) 0.27 A \[{{P}_{1}}\] to \[{{P}_{2}}\]
C) 0.27 A \[{{P}_{2}}\] to \[{{P}_{1}}\]
D) 0.03 A \[{{P}_{1}}\] to \[{{P}_{2}}\]
Correct Answer: A
Solution :
\[i=\frac{{{\varepsilon }_{1}}{{r}_{2}}+{{\varepsilon }_{2}}{{r}_{1}}}{{{r}_{1}}{{r}_{2}}+R{{r}_{1}}+R{{r}_{2}}}=\frac{5\times 1+\left( -2 \right)\times 2}{2\times 1+10\times 2+10\times 1}\] = 0.03 A
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