A) no value of p
B) exactly one value of p
C) exactly two values of p
D) more than two values of p
Correct Answer: B
Solution :
\[p({{p}^{2}}+1)=\frac{-{{({{p}^{2}}+1)}^{2}}}{{{p}^{2}}+1}\] \[y=q\] \[x+y+2q=0\] \[\Rightarrow \]\[p=1.\]You need to login to perform this action.
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