A) 0.25
B) 0.5
C) 0.75
D) 0.99
Correct Answer: C
Solution :
\[\eta =\left( 1-\frac{{{T}_{2}}}{{{T}_{1}}} \right)\] \[\because \]\[{{T}_{1}}V_{1}^{\gamma -1}={{T}_{2}}V_{2}^{\gamma -1}\] \[\therefore \]\[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}={{\left( \frac{1}{32} \right)}^{\gamma -1}}\] Putting \[\gamma =7\text{ }/\text{ }5\] \[\eta =\left( 1-\frac{1}{4} \right)=\frac{3}{4}=0.75\]
You need to login to perform this action.
You will be redirected in
3 sec
