AIEEE Solved Paper-2010
A) \[4.9\text{ }m{{s}^{2}}\]in vertical direction
B) \[4.9\text{ }m{{s}^{2}}\] in horizontal direction
C) \[9.8\text{ }m{{s}^{2}}\]in vertical direction
D) Zero
Correct Answer: A
Solution :
\[{{a}_{{{A}_{vertical}}}}=g{{\sin }^{2}}{{60}^{o}}=\frac{3g}{4}\] \[{{a}_{{{B}_{vertical}}}}=g{{\sin }^{2}}{{30}^{o}}=\frac{g}{4}\] So,\[{{a}_{AB}}=\frac{g}{2}=4.9\,m{{s}^{-2}}vertical\]
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