A) 29.5
B) 59.0
C) 47.4
D) 23.7
Correct Answer: D
Solution :
Equation of\[N{{H}_{3}}\] \[=(0.1\times 20)-(0.1\times 15)=0.5\] wt. of\[N{{H}_{3}}\] \[=0.5\times 17=8.5mg\] wt. of 'N' \[=\frac{14}{17}\times 8.5mg=7mg\] % of \['N'=\frac{7}{29.5}\times 100=23.7\]You need to login to perform this action.
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