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JEE Main & Advanced AIEEE Solved Paper-2010

  • question_answer
    If\[{{10}^{-4}}d{{m}^{-3}}\]of water is introduced into a 1.0\[d{{m}^{-3}}\]flask at 300 K, how many moles of water are in in the vapour phase when equilibrium is established? (Given: Vapour pressure of \[{{H}_{2}}O\]at 300 is 3170 pa;\[R=8.314\text{ }J\text{ }{{K}^{-1}}mo{{l}^{-1}})\]       AIEEE  Solved  Paper-2010

    A) \[1.27\times 10\text{ }mo{{l}^{-3}}\]

    B)        \[5.56\times 10\text{ }mo{{l}^{-3}}\]     

    C) \[1.53\times 10\text{ }mo{{l}^{-2}}\]

    D)        \[4346\times 10\text{ }mo{{l}^{-2}}\]

    Correct Answer: A

    Solution :

    \[PV=nRT\] \[3170\frac{N}{{{m}^{2}}}\times {{10}^{-3}}{{m}^{3}}=n\times 8.314\times 300\] \[n=\frac{3170\times {{10}^{-3}}}{24.93\times {{10}^{-2}}}=\frac{31.7\times {{10}^{-1}}}{24.93\times {{10}^{-2}}}=1.287\times {{10}^{-1}}m\]


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