A) 8
B) 9
C) 10
D) 11
Correct Answer: C
Solution :
\[{{K}_{sp}}=[M{{g}^{+2}}]{{[O{{H}^{-}}]}^{2}}\] \[1\times {{10}^{-11}}=[0.001]{{[O{{H}^{-}}]}^{2}}\] \[[o{{h}^{-}}]={{10}^{-4}}\] \[P\text{ }on=4;\text{ }pn=10\]You need to login to perform this action.
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