A) 310 K and 248 K
B) 372 K and 310 K
C) 372 K and 330 K
D) 330 K and 268 K
Correct Answer: B
Solution :
\[\frac{1}{6}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\Rightarrow \frac{{{T}_{2}}}{{{T}_{1}}}=\frac{5}{6}\] Also, \[\frac{{{T}_{2}}-62}{{{T}_{1}}}=\frac{2}{3}\] \[\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{5}{6}\] \[\Rightarrow \,\,\,\frac{{{T}_{2}}-62}{{{T}_{2}}}=\frac{4}{5}\] or \[{{T}_{2}}=62\times 5\] or \[{{T}_{2}}=310\,\,K\] \[\Rightarrow \,\,\,{{T}_{2}}=372\,\,K\]
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