A) Benzophenone
B) Acetaldehyde
C) Acetone
D) Formaldehyde
Correct Answer: B
Solution :
Both formaldehyde and acetaldehyde will give this test \[HCHO\xrightarrow{[Ag(N{{H}_{3}})_{2}^{+}]}\underset{Silver\,\,mirror}{\mathop{Ag\downarrow }}\,+\]Organic compound \[C{{H}_{3}}-CHO\xrightarrow{{{[Ag{{(N{{H}_{3}})}_{2}}]}^{+}}}\underset{Silver\,\,mirror}{\mathop{Ag\downarrow }}\,+\] Organic Compound
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