A) \[-2\]
B) 7
C) 5
D) 13
Correct Answer: B
Solution :
We have \[\frac{dy}{dx}=y+3\] \[\Rightarrow \,\,\frac{1}{y+3}dy=dx\] \[\Rightarrow \] ln \[\left| (y+3) \right|=x+k\], where k is a constant of integration \[\Rightarrow \,\,(y+3)=c\,{{e}^{x}}\] Initially when \[x=0\,,y=2\] \[\Rightarrow \,c=5\] Finally the required solution is \[y+3=5{{e}^{x}}\] \[\Rightarrow \,y(In2)=5{{e}^{In2}}-3=10-3=7\]
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