A) 4
B) 11
C) 5
D) 0
Correct Answer: B
Solution :
\[\because \]\[1\left| \begin{matrix} 1 & \alpha & 3 \\ 1 & 3 & 3 \\ 2 & 4 & 4 \\ \end{matrix} \right|1=|A{{|}^{2}}={{4}^{2}}\] \[2\alpha -6=16\] \[\therefore \] \[\alpha =11.\]You need to login to perform this action.
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