JEE Main & Advanced AIEEE Solved Paper-2013

  • question_answer
    The expression\[\frac{\tan A}{1-\cot A}+\frac{\cot A}{1-\tan A}\]can be written as:     AIEEE Solevd Paper-2013

    A) \[sinA\text{ }cosA+1\]  

    B)  \[secA\text{ }cosecA+1\]           

    C) \[tanA+cotA\]  

    D) \[secA+cosecA\]

    Correct Answer: B

    Solution :

    \[Exp.=\frac{{{\tan }^{2}}A}{\tan A-1}+\frac{1}{\tan A-{{\tan }^{2}}A}\] \[=\frac{1}{tanA-1}\left[ {{\tan }^{2}}A-\frac{1}{\tan A} \right]\] \[=\frac{{{\tan }^{2}}A+\tan A+1}{\tan A}=\tan A+\cot A+1\] \[=\sec A.\cos ecA+1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner