A) \[+2\]
B) \[+4\]
C) \[+6\]
D) \[+7\]
Correct Answer: C
Solution :
Let the oxidation number of \[Cr\] in \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] be x oxidation number of \[O=-2;K=+1\] \[\therefore \] \[2\times +1+2x+7\times -2=0\] \[2x=12\] \[x=+6\]You need to login to perform this action.
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