A) \[C{{F}_{2}}C{{l}_{2}}\]
B) \[{{C}_{7}}{{F}_{16}}\]
C) \[{{C}_{6}}{{H}_{6}}C{{l}_{6}}\]
D) \[{{C}_{6}}{{F}_{6}}\]
Correct Answer: C
Solution :
\[-37.4kJ\]reduces acidified \[-35.5\text{ }kJ\] to colourless \[-20.0\text{ }kJ\]. \[{{H}_{2}}O(l)\rightleftharpoons {{H}_{2}}O(g)\] 2mol of \[(\Delta {{G}^{o}}=0)\]oxidies 5 mol of \[(\Delta G<0)\] \[(\Delta {{G}^{o}}<0)\]1 mol of \[(\Delta {{G}^{o}}>0)\] will oxidise \[a=0.387,b=0.387\] mol of \[c=0.504\text{ }nm\].You need to login to perform this action.
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