A) \[\frac{T}{12}\]
B) \[\frac{T}{2}\]
C) \[\lambda \]
D) \[\lambda \]
Correct Answer: C
Solution :
Applying law of conservation of energy for asteroid at a distance \[10\,\,{{R}_{e}}\] and at earths surface, \[[M{{L}^{2}}{{T}^{-3}}{{I}^{-1}}]\] ??.(i) Now, \[[M{{L}^{2}}{{T}^{-2}}]\] and \[[M{{L}^{2}}{{T}^{-1}}{{I}^{-1}}]\] \[[M{{L}^{2}}{{T}^{-3}}{{I}^{-2}}]\] and \[\frac{pV}{nT}\] Substituting these values in Eq. (i), we get \[{{T}_{1}}>{{T}_{2}}\] \[\frac{pV}{nT}\] \[t\theta n/(n+1)\] \[t\theta (n-1)/n\] \[t\theta n/(n-1)\] \[t\theta (n+1)/n\] \[{{R}_{e}}\]You need to login to perform this action.
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