A) \[\pi /\omega \]
B) \[\frac{4}{3}\]
C) \[36\sqrt{7}\]
D) \[\frac{36}{\sqrt{7}}\]
Correct Answer: B
Solution :
The situation is shown in figure. \[\frac{G{{m}_{1}}{{m}_{2}}}{r}=\frac{1}{2}{{m}_{1}}v_{1}^{2}+\frac{1}{2}{{m}_{2}}v_{2}^{2}\] \[\Rightarrow \] \[\frac{m_{1}^{2}v_{1}^{2}}{{{m}_{1}}}+\frac{m_{2}^{2}v_{2}^{2}}{{{m}_{2}}}=\frac{2G{{m}_{1}}{{m}_{2}}}{r}\] \[{{v}_{1}}=\sqrt{\frac{2GM_{2}^{2}}{r({{m}_{1}}+{{m}_{2}})}}\] or \[{{v}_{2}}=\sqrt{\frac{2Gm_{1}^{2}}{r({{m}_{1}}+{{m}_{2}})}}\] \[\therefore \]You need to login to perform this action.
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