A) L = R
B) L = \[\frac{M{{L}^{2}}}{12}+\frac{M{{R}^{2}}}{4}=\frac{M{{R}^{2}}}{2}\] R
C) \[L=\frac{R}{\sqrt{3}}\]
D) \[L=\sqrt{\frac{3}{2}}R\]
Correct Answer: B
Solution :
(I) Moment of inertia of a cylinder about its centre and parallel to its length \[\beta \] (II) Moment of inertia about its centre and perpendicular to its length \[M=\left( \frac{{{L}^{2}}}{12}+\frac{{{L}^{2}}}{4} \right)\] According to question \[\frac{L}{R}\] or \[\left( \frac{L}{R} \right)\]You need to login to perform this action.
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