A) \[+3\]
B) \[+2\]
C) \[+6\]
D) \[+4\]
Correct Answer: A
Solution :
\[C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{I}^{-}}\to 2C{{r}^{3+}}+7{{H}_{2}}O+3{{I}_{2}}\] \[C{{r}_{2}}O_{7}^{2-}\] is reduced to \[C{{r}^{3+}}\]. Thus, final state of Cr is +3.You need to login to perform this action.
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