A) \[168\text{ }g\]
B) \[84\text{ }g\]
C) \[42\text{ }g\]
D) \[21\text{ }g\]
Correct Answer: C
Solution :
\[4\times 18g\,{{H}_{2}}O\equiv 3\times 56gFe\] \[\therefore \] \[18g{{H}_{2}}O=\frac{3\times 56}{4}\] \[\equiv 42g\]You need to login to perform this action.
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