NEET AIPMT SOLVED PAPER 1999

  • question_answer
                      A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomes:                                                                             

    A)                 \[\sqrt{2}\,C\]                  

    B)                 2C                          

    C)                 \[\frac{C}{\sqrt{2}}\]                     

    D)                 \[\frac{C}{2}\]

    Correct Answer: D

    Solution :

                    The capacitance of a parallel plate capacitor with dielectric (oil) between its plates is.                 \[C=\frac{K{{\varepsilon }_{0}}A}{d}\]                    ...(i)                 where \[{{\varepsilon }_{0}}\] = electric permittivity of free space                 K = dielectric constant                 A = area of each plate of capacitor                 d = distance between two plates                 When dielectric (oil) is removed, so capacitance                 \[{{C}_{0}}=\frac{{{\varepsilon }_{0}}A}{d}...(ii)\]                 Comparing Eqs. (i) and (ii), we get                 \[C=K{{C}_{0}}\] \[\Rightarrow {{C}_{0}}=\frac{C}{K}=\frac{C}{2}(K=2)\]


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