A) 0.2 T
B) \[2\times {{10}^{-4}}T\]
C) \[6.28\times {{10}^{-4}}T\]
D) \[9.8\times {{10}^{-4}}T\]
Correct Answer: C
Solution :
At the centre of circular coil carrying current, the magnetic field is, \[B=\frac{{{\mu }_{0}}Ni}{2r}\] where N = number of turns in the coil i = current flowing r = radius of the coil Given, N = 1000, i = 0.1 A, r = 0.1 m Substituting the values, we have \[B=\frac{4\pi \times {{10}^{-7}}\times 1000\times 0.1}{2\times 0.1}\] \[=2\pi \times {{10}^{-4}}=6.28\times {{10}^{-4}}\,tesla\] Note: Tesla is the unit of B is SI system. In the same system the unit of B is also \[Wb/{{m}^{2}}\]. In the CGS system, its unit is gauss.
You need to login to perform this action.
You will be redirected in
3 sec
