2. Solved Papers
  3. NEET

NEET AIPMT SOLVED PAPER 1999

  • question_answer
                            The uncertainty in momentum of an electron is \[1\times {{10}^{-5}}\,m/s\]. The uncertainty in its position will be\[(h=6.62\times {{10}^{-34}}\,kg\,{{m}^{2}}/s)\]:                                                                                                                        

    A)              \[1.05\times {{10}^{-28}}\,m\]

    B)              \[1.05\times {{10}^{-26}}\,m\]

    C)              \[5.27\times {{10}^{-30}}\,m\]

    D)              \[5.25\times {{10}^{-28}}\,m\]

    Correct Answer: C

    Solution :

                    According to Heisenberg uncertainty principle:                 \[\Delta p\times \Delta x\ge \frac{h}{4\pi }\]                 \[1\times {{10}^{-5}}\times \Delta x=\frac{6.62\times {{10}^{-34}}}{4\times \frac{22}{7}}\]                         \[\Delta x=\frac{6.62\times {{10}^{-34}}\times 7}{1\times {{10}^{-5}}\times 22}=5.265\times {{10}^{-30}}\,m\]             \[\approx \,5.27\times {{10}^{-30}}\,m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner