2. Solved Papers
  3. NEET

NEET AIPMT SOLVED PAPER 1999

  • question_answer
                    Two racing cars of masses m1 and m2 are moving in circles of radii \[{{r}_{1}}\] and \[{{r}_{2}}\] respectively. Their speeds are such that each makes a complete circle in the same time t. The ratio of the angular speeds of the first to the second car is:      

    A)                                                                                                                                                            1 : 1

    B)                 \[{{m}_{1}}:{{m}_{2}}\]                

    C)                 \[{{r}_{1}}:{{r}_{2}}\]                     

    D)                 \[{{m}_{1}}:{{m}_{2}}:{{r}_{1}}{{r}_{2}}\]

    Correct Answer: A

    Solution :

                    Angular speed                 \[\frac{Angle\,traversed\,in\,one\,revolution}{Time-period}\]                 So,          \[\omega =\frac{2\pi }{t}\]                 As T is same for both racing cars, therefore angular speed to is same for both cars.                 i.e.,        \[\frac{{{\omega }_{1}}}{{{\omega }_{2}}}=1\]                 or           \[{{\omega }_{1}}\,:\,{{\omega }_{2}}=1:1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner