A) \[1\times {{10}^{23}}\]
B) \[2\times {{10}^{23}}\]
C) \[4\times {{10}^{23}}\]
D) \[6\times {{10}^{23}}\]
Correct Answer: D
Solution :
Weight of \[N{{H}_{3}}=4.25\,g\] Number of moles of \[N{{H}_{3}}\] \[=\frac{Wt.}{Mol.\,wt.}=\frac{4.25}{17}=0.25\] Number of molecules in 0.25 mole of \[N{{H}_{3}}\] \[=0.25\times 6.023\times {{10}^{23}}\] So, number of atoms = \[4\times 0.25\times 6.023\times {{10}^{23}}\] \[=6.0\times {{10}^{23}}\]
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