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NEET AIPMT SOLVED PAPER 2000

  • question_answer
                                    A nuclear decay is expressed as                                                                                                                                \[_{6}{{C}^{11}}\to {{\,}_{5}}{{B}^{11}}+\,{{\beta }^{+}}+X\]                 Then the unknown particle X is:

    A)                 neutron      

    B)                 antineutrino      

    C)                 proton   

    D)                 neutrino

    Correct Answer: D

    Solution :

                    Key Idea: In a nuclear reaction conservation of charge number and mass number must hold good.                 Let Z be the charge number and A the mass number of particle X, then conservation of charge number gives.                 6 = 5 + 1 + Z                                           \[\Rightarrow Z=0\]                 Conservation of mass number gives,                 11 = 11 + 0 + A                 \[\Rightarrow \]               A = 0                 X is a particle of zero charge and zero mass. This particle may be neutrino or antineutrino. With positive \[\beta \]-particle, neutrino is emitted and with negative \[\beta \]-particle, antineutrino is emitted.                 Thus, in our case neutrino will be emitted.


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