2. Solved Papers
  3. NEET

NEET AIPMT SOLVED PAPER 2000

  • question_answer
                    A cell has an emf 1.5 V. When connected across an external resistance of \[2\,\Omega \], the terminal potential difference falls to 1.0 V. The internal resistance of the cell is:

    A)                                                                         \[2\,\Omega \]

    B)                        \[1.5\,\Omega \]             

    C)                 \[1.0\,\Omega \]             

    D)                 \[0.5\,\Omega \]

    Correct Answer: C

    Solution :

                    Internal resistance of the cell is given by                 \[r=\left( \frac{E-V}{V} \right)R\]                 Given, E = 1.5 V, V = 1.0 V,R = 2 \[\Omega \]                 \[\therefore r=\left( \frac{1.5-1.0}{1.0} \right)\times 2=\frac{0.5}{1.0}\times 2=1.0\,\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner