A) \[{{K}_{{{a}_{2}}}}={{K}_{{{a}_{1}}}}\]
B) \[{{K}_{{{a}_{2}}}}>{{K}_{{{a}_{1}}}}\]
C) \[{{K}_{{{a}_{2}}}}<{{K}_{{{a}_{1}}}}\]
D) \[{{K}_{{{a}_{2}}}}=\frac{1}{K{{a}_{1}}}\]
Correct Answer: C
Solution :
\[{{H}_{2}}X\rightleftharpoons {{H}^{+}}+\,H\,{{X}^{-}}({{K}_{{{a}_{1}}}})\] \[H{{X}^{-}}\rightleftharpoons {{H}^{+}}+{{X}^{2-}}({{K}_{{{a}_{2}}}})\] In the 1st equation hydrogen ion is formed from neutral molecule whereas in IInd equation it comes from negatively charged species. Due to negative charge removal of proton is difficult. \[So,{{K}_{{{a}_{1}}}}>{{K}_{{{a}_{2}}}}\]
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