A) the e/m of electrons is greater than the e/m of protons
B) the e/m ratio of the cathode-ray particles changes when a different gas is placed in the discharge tube
C) cathode rays axe streams of negatively charged ions
D) all the mass of an atom is essentially in the nucleus
Correct Answer: A
Solution :
J.J. Thomson's cathode-ray tube experiment demonstrated the relation for e/m of chared particles. The relation is \[\frac{e}{m}=\frac{{{E}^{2}}}{2{{B}^{2}}V}\] Thus, knowing B, B and V, the Value of e/m for electrons and protons can be calculated. It is found the e/m of electrons is much greatest than the e/m of protons.
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