A) \[f,\,1,\,2\lambda \]
B) \[0.8f,\,0.8\lambda \]
C) \[1.2f,\,1.2\lambda \]
D) \[1.2\,f,\,\lambda \]
Correct Answer: D
Solution :
When an observer moves towards an stationary source of round, then apparent frequency heard by the observer increases. The apparent frequency heard in this situation \[f'=\left( \frac{v+{{v}_{0}}}{v-{{v}_{s}}} \right)\,f\] As source is stationary hence, \[{{v}_{s}}=0\] \[\therefore f'=\left( \frac{v+{{v}_{0}}}{v} \right)\,f\] Given, \[{{v}_{0}}=\frac{v}{5}\] Substituting in the relation for\[f'\], we have \[f'=\left( \frac{v+v/5}{v} \right)f\] \[=\frac{6}{5}f=1.2\,f\]
You need to login to perform this action.
You will be redirected in
3 sec
