question_answer

                In a set of the given reactions, acetic acid yielded a product C,                                                                 \[C{{H}_{3}}COOH+PC{{l}_{5}}\to A\xrightarrow[Anh.\,AlC{{l}_{3}}]{{{C}_{6}}{{H}_{6}}}B\underset{Ether}{\mathop{\xrightarrow{{{C}_{2}}{{H}_{5}}MgBr}}}\,C\]                 product C would be:

A)                 \[C{{H}_{3}}CH(OH){{C}_{6}}{{H}_{5}}\]                            

B)                 \[C{{H}_{3}}-\overset{\begin{smallmatrix}  {{C}_{2}}{{H}_{5}} \\  | \end{smallmatrix}}{\mathop{C(OH){{C}_{6}}{{H}_{5}}}}\,\]

C)                 \[C{{H}_{3}}CH(OH){{C}_{2}}{{H}_{5}}\]            

D)                 \[C{{H}_{3}}CO{{C}_{6}}{{H}_{5}}\]

Correct Answer: B

Solution :

                \[C{{H}_{3}}COOH+PC{{l}_{5}}\xrightarrow[{}]{{}}C{{H}_{3}}\underset{(A)}{\mathop{COCl}}\,\]