A) \[\text{44}\,\text{g}\,\text{C}{{\text{O}}_{\text{2}}}\]
B) \[\text{48}\,\text{g}\,{{\text{O}}_{3}}\]
C) \[\text{8}\,\text{g}\,{{\text{H}}_{\text{2}}}\]
D) \[\text{64}\,\text{g}\,\text{S}{{\text{O}}_{\text{2}}}\]
Correct Answer: C
Solution :
\[\text{44}\,\text{g}\,\text{C}{{\text{O}}_{\text{2}}}\text{=1mol}\,\text{C}{{\text{O}}_{\text{2}}}\text{=}\,{{\text{N}}_{\text{A}}}\text{molecules}\,\text{of}\,\text{C}{{\text{O}}_{\text{2}}}\] \[\text{48}\,\text{g}\,{{\text{O}}_{3}}\text{=1mol}\,{{\text{O}}_{3}}\text{=}\,{{\text{N}}_{\text{A}}}\text{molecules}\,\text{of}\,{{\text{O}}_{3}}\] \[\text{8}\,\text{g}\,{{\text{H}}_{2}}\text{=4}\,\text{mol}\,{{\text{H}}_{2}}\text{=}\,\text{4}\times \,{{\text{N}}_{\text{A}}}\text{molecules}\,\text{of}\,{{\text{H}}_{\text{2}}}\] \[64\,\text{g}\,\text{S}{{\text{O}}_{2}}\text{=}\,1\,\text{mol}\,\text{S}{{\text{O}}_{2}}\text{=}\,\,{{\text{N}}_{\text{A}}}\text{molecules}\,\text{of}\,\text{S}{{\text{O}}_{\text{2}}}\]
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