A) \[-0.18{}^\circ C\]
B) \[-0.54{}^\circ C\]
C) \[-0.36{}^\circ C\]
D) \[-0.24{}^\circ C\]
Correct Answer: D
Solution :
Freezing point depression\[(\Delta {{T}_{f}})=i{{K}_{f}}m\] \[\underset{\begin{smallmatrix} 1-\alpha \\ 1-0.3 \end{smallmatrix}}{\mathop{\text{HA}}}\,\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} \alpha \\ 0.3 \end{smallmatrix}}{\mathop{{{\text{H}}^{\text{+}}}}}\,+\underset{\begin{smallmatrix} \alpha \\ 0.3 \end{smallmatrix}}{\mathop{{{\text{A}}^{-}}}}\,\] \[i=1-0.3+0.3+0.3\] \[i=1.3\] \[\therefore \] \[\Delta {{T}_{f}}=1.3\times 1.86\times 0.1={{0.2418}^{o}}C\] \[{{T}_{f}}=0-{{0.2418}^{o}}C\] \[=-{{0.2418}^{o}}C\]
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