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NEET AIPMT SOLVED PAPER SCREENING 2004

  • question_answer
    A coil of 40 H inductance is connected in series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 V battery. The time constant of the circuit is:                                     

    A) 5 s   

    B)               1/5 s             

    C) 40 s               

    D) 20 s

    Correct Answer: A

    Solution :

      Time constant of L-R circuit is, \[\tau =\frac{L}{R}\] Here, \[L=40H,R=8\Omega ,\,\,E=2\text{V}\] \[\therefore \]\[\tau =\frac{40}{8}=5s\] NOTE: At a time equal to one time constant the current has risen to \[\left( 1-\frac{1}{\theta } \right)\] or about 63% of its initial


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