question_answer

\[{{H}_{2}}O\]is dipolar, whereas \[Be{{F}_{2}}\] is not. It is because:                                                                             

A) the electro negativity of F is greater than that of O

B) \[{{H}_{2}}O\]involves hydrogen bonding whereas\[Be{{F}_{2}}\] is a discrete molecule

C) \[{{H}_{2}}O\] is linear and \[Be{{F}_{2}}\] is angular

D) \[{{H}_{2}}O\]is angular and \[Be{{F}_{2}}\] is linear

Correct Answer: D

Solution :

  The structure of \[{{H}_{2}}O\]is angular V-shape and as\[s{{p}^{3}}\]-hybridisation and bond angle is \[{{105}^{\text{o}}}\]. Its dipole moment value is positive or more than zero. but in \[Be{{F}_{2}}\], structure is linear due to sp-hybridization\[(\mu =0)\] Thus, due to \[\mu >0,\,{{H}_{2}}O\]is dipolar and due to\[\mu =0,\]\[Be{{F}_{2}}\] is non-polar.