A) \[{{20}^{\text{o}}}C\]
B) \[{{320}^{\text{o}}}C\]
C) \[-{{20}^{\text{o}}}C\]
D) \[{{40}^{\text{o}}}C\]
Correct Answer: C
Solution :
Key Idea: The temperature of inversion is higher than the neutral temperature by the same amount as the neutral temperature is higher than the temperature of cold junction. As per Key Idea \[{{t}_{n}}-{{t}_{0}}={{t}_{i}}-{{t}_{n}}\] \[\Rightarrow {{t}_{0}}=2{{t}_{n}}-{{t}_{i}}\] Given, \[{{t}_{i}}={{620}^{o}}C,\,\,{{t}_{n}}={{300}^{o}}C\] Hence, \[{{t}_{0}}=\] temperature of cold junction \[=2\times 300\,-620\] \[=600-620\,=-{{20}^{\text{o}}}C\] Note: Neutral temperature does not change for a metal whether the temperature of cold junction and inversion temperature change by any value.
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