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NEET AIPMT SOLVED PAPER SCREENING 2005

  • question_answer
                    A force F acting on an object varies with distance \[x\] as shown here. The force is in N and \[x\] is in m. The work done by the force in moving the object from x = 0 to x = 6 m is:                                                     

    A)                 4.5 J    

    B)                 13.5 J

    C)                 9.0 J    

    D)                 18.0 J

    Correct Answer: B

    Solution :

                              Key Idea: The work done will be the area of the F-x graph.                           Work done in moving the object from x = 0 to x = 6 m is given by                 W = area of rectangle + area of triangle                 \[=3\times 3+\frac{1}{2}\,\times 3\times 3\]                 = 9 + 4.5 = 13.5 J


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