A) \[c+a-b\]
B) \[c-a-b\]
C) \[a+b+c\]
D) \[a+b-c\]
Correct Answer: B
Solution :
Key Idea: The energy released per nuclear reaction is the resultant binding energy. Binding energy of (\[_{1}^{2}H\] + \[_{1}^{3}H\]) = a + b Binding energy of \[_{2}^{4}He\] = c In a nuclear reaction the resultant nucleus is more stable than the reactants. Hence, binding energy of \[_{2}^{4}He\] will be more than that of \[\left( _{1}^{2}H+\,_{1}^{3}H \right)\] Thus, energy released per nucleon = resultant binding energy \[=c-(a+b)=c-a-b\] Note: Out of the elements present in periodic table, Fe(56) has maximum binding energy. Hence it is most stable.You need to login to perform this action.
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