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NEET AIPMT SOLVED PAPER SCREENING 2007

  • question_answer
                    Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYV and rryy genotypes are hybridized, then \[{{F}_{2}}\] segregation will show:                                                               

    A)                  higher number of the recombinant types

    B)                  segregation in the expected 9 : 3 : 3 : 1 ratio

    C)                  segregation in 3 : 1 ratio                              

    D)                  higher number of the parental types

    Correct Answer: D

    Solution :

                    Law of independent assortment does not applicable when the gene of different character occupy on the same homologous chromosome i.e., linked gene.


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