The work done in charging fully both the condensers is:
A) \[2C{{V}^{2}}\]
B) \[\frac{1}{4}\,C{{V}^{2}}\]
C) \[\frac{3}{4}\,C{{V}^{2}}\]
D) \[\frac{1}{2}\,C{{V}^{2}}\]
Correct Answer: C
Solution :
The two condensers in die circuit are in parallel order, hence \[C'=C+\frac{C}{2}=\frac{3C}{2}\] The work done in charging the equivalent capacitor is stored in the form of potential energy. Hence \[W=U=\frac{1}{2}C'\,{{V}^{2}}\] \[=\frac{1}{2}\,\left( \frac{3C}{2} \right){{V}^{2}}\] \[=\frac{3}{4}C{{V}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
