A) \[\frac{3}{5}\]
B) \[\frac{4}{5}\]
C) \[\frac{2}{5}\]
D) 1
Correct Answer: C
Solution :
\[2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}+2MnS{{O}_{4}}+3{{H}_{2}}O+5[O]\] \[[MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\xrightarrow{{}}M{{n}^{2+}}+4{{H}_{2}}O]\times 2\] \[\underline{(SO_{3}^{2-}+{{H}_{2}}O\xrightarrow{{}}SO_{4}^{2-}+2{{H}^{+}}+2{{e}^{-}})\times 5}\] \[\begin{align} & 2MnO_{4}^{-}+6{{H}^{+}}+5SO_{3}^{2-}\xrightarrow[{}]{{}} \\ & 2M{{n}^{2+}}+SO_{4}^{2-}+3{{H}_{2}}O \\ \end{align}\] 5 moles of sulphite ion react with = 2 moles of \[MnO_{4}^{-}\] So, 1 mole of sulphite ion react with = \[\frac{2}{5}\]moles of \[MnO_{4}^{-}\].
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