A) \[\begin{align} & \,\,\,\,\,\,\,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}} \\ & {{H}_{3}}C-\overset{|}{\mathop{\underset{|}{\mathop{C}}\,}}\,-Cl \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,H \\ \end{align}\]
B) \[H-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\overset{\begin{smallmatrix} {{C}_{2}}{{H}_{5}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\]
C) \[\begin{align} & \,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}} \\ & Cl-\overset{|}{\mathop{\underset{|}{\mathop{C}}\,}}\,-C{{H}_{3}} \\ & \,\,\,\,\,\,\,\,\,\,H \\ \end{align}\]
D) \[\begin{align} & \,\,\,\,\,\,\,\,C{{H}_{3}} \\ & H-\overset{|}{\mathop{\underset{|}{\mathop{C}}\,}}\,-Cl \\ & \,\,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}} \\ \end{align}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}-CHCl-C{{H}_{2}}-C{{H}_{3}}\] Priority order is
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